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7n^2+14n-21=0
a = 7; b = 14; c = -21;
Δ = b2-4ac
Δ = 142-4·7·(-21)
Δ = 784
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$n_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$n_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{784}=28$$n_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(14)-28}{2*7}=\frac{-42}{14} =-3 $$n_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(14)+28}{2*7}=\frac{14}{14} =1 $
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